Surveying MCQs Ch 9 Curves

Surveying MCQs 
Chapter 9 

Curves

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Surveying MCQs 
Chapter 9 

Curves

Q.1. The length of a unit chord should not be more than

a) 1/20th of the radius ✔

b) 1/10th of the radius

c) 1/40th of the radius

d) 1/50th of the radius

Q.2. The length of the tangent of a curve whose radius is R and the angle of deflection Δ is

a) R tan Δ/2 ✔

b) 2R tan Δ/2

c) R sin Δ/2

d) 2R sin Δ/2

Apex Distance or External Distance = R [secΔ/2 -1]
Length of curve = πRΔ/180
Tangent Length =R tan Δ/2
Length of long chord = 2R sin Δ/2
Mid-Ordinate or versine of curve= R (1 - cosΔ/2)

Q.3. Point of tangency is the______.

a) Beginning of the curve

b) End of the curve

c) Common point where the radius changes

d) Common point where the radius and direction change ✔

Q.4. A curve whose radius varies from infinity to a certain value is called_______.

a) Compound curve

b) Circular curve

c) Reverse curve

d) Transition curve ✔

Q.5. Which of the following is CORRECT for the length of the curve? 

a) It Is Inversely proportional to radius of the curve.

b) It Is Inversely proportional to square radius of the curve.

c) It Is proportional to deflection angle. ✔

d) It is proportional to degree of the curve.

Q.6. calculate the apex distance, If the deflection angle is 60 degree and the degree of curve Is 8 degree. 

a) 33.26 ✔

b) 127.13

c) 215

d) 262.8

Apex Distance or External Distance = R [secΔ/2 -1]
R = 1720/D = 1720/8 = 215 m
∴ Apex Distance or External Distance = 215 [sec 60/2 -1] = 33.26 m

Q.7. Calculate the length (m) tangent of a 5 degree curve, If the deflection angle Is 60 degree. 

a) 172.5

b) 390

c) 198.6 ✔

d) 596

Tangent Length =R tan Δ/2
R = 1720/D = 1720/5 = 344
∴ Tangent Length =R tan Δ/2 = 344 tan 60/2 = 198.61 m

Q.8. What is the degree of the curve (in degree) of a radius of 573m using chain of 20m length 

a) 1

b) 2  ✔

c) 3

d) 4

R = 1146 / D
∴ D = 1146 / 573
D = 2°

Q.9. Calculate the length (m) of the longer chord of 250m radius curve having deflection angle of 90 degree. 

a) 250 m

b) 353.6 m ✔

c) 392.7 m

d) 500 m

Length of long chord = 2R sin Δ/2
= 2 x 250 x sin 90/2
= 353.6 m

Q.10. The degree of curve for a 30 m chain Is : 

a) 1718.9 x R ✔

b) 1145.92/R

c) 1718.9/R

d) 1145.92 x R

The degree of curve for a 20 m chain = 1145.9 /D

Please comment for any improvement 

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