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Daily Quiz 65

Daily Quiz

Daily Quiz 65


civil engineering mcqs, mcqs in civil engineering, mcqs of civil engineering, civil engineering solved mcq pdf, civil engineering mcqs pdf,civil engineering mcq questions, civil engineering mcq book,WRD Quiz, SSC JE Quiz, RRB Quiz, Rajasthan JE Quiz, Civil Engineering  MCQ, Mahpariksha Civil Engineering  Objectives, JE Questions civil engineering

This Daily Quizzes is made up for daily practicing objective type questions both technical as well as non technical. In this Quizzes Questions are added from previous year question papers such as Mahapariksha PWD, Mahapariksha Town planning, Mahapariksha Soil and Water Conservation Department, WRD, Rajasthan JE, ITI Lecturer, SSC, RRB, BMC, GATE, ISRO, MPSC, UPSC, APPSC, Metro and also from objectives types books . I hope this is helpful for your upcoming Exams ✌.

All the best for your all upcoming Exams 👍💐💐💐


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Daily Quiz 65




Q.1. The size of mould used for making bricks compared to size of brick is

a) 10% more 
b) 5% more
c) exactly equal
d) 5% less

Q.2. For hilly region the ideal method of contouring is

a) direct method
b) method of squares
c) cross-section method
d) radial line method 

Q.3. In case of a beam with triangular section of base width 200 mm and height 100 mm, maximum shear stress due to a shear force of 20 kN is

a) 2.67 N/mm²
b) 3.0 N/mm² 
c) 1.33 N/mm²
d) 1.5 N/mm²

Maximum Shear stress is occur @ h/2 = 1.5 times avg shear stress
Shear stress @ N.A. = 4/3 times avg shear stress
Avg Shear stress = P/A = (20x1000) / 0.5x200x100 = 2
∴ Maximum Shear stress = 1.5 x 2 = 3 N/mm²

Q.4. ‘If an internal stress component like shear force, bending moment or reaction component is allowed to act through a small distance thereby causing deformation of the structure, the curve of the deformed shape represents to some scale, the influence line diagram for that stress or the reaction component'. The above statement is known as

a) Mecaulay’s theorem
b) Muller–Breslau principle 
c) Castigliano’s theorem
d) Maxwell’s theorem

Q.5. If a roof is sloping at 12°, imposed load to be considered in the design is

a) 1.5 kN/m²
b) 1.0 kN/m²
c) 0.75 kN/m² 
d) 0.71 kN/m² 

Imposed load for 10° slopping = 0.75 kN/m²
Note :- 0.02 kN/m² less for every degree increase in slope over 10°
∴ for 12° slopping = 0.75 - 0.02x2 = 0.71 kN/m²

Q.6. Minimum thickness of footing shall be 
        A: for footing on soil –150 mm 
        B: for footing on piles –250 mm 
        Select your answer code

a) Both A and B are true
b) A is true but B is false 
c) A is false but B is true
d) Both A and B are false

Minimum thickness shall be
– 150 mm for footing on soil
– 300 mm for footing on piles.

Q.7. If t is the thickness of thinner plate jointed by intermittent weld, minimum spacing recommended in tension and compression joints are respectively

a) 12 t and 16 t
b) 16 t and 12 t 
c) 16 t and 20 t
d) 20 t and 16 t

Q.8. Venturimeter should be preceded by a straight portion of the pipe of length ______ times the diameter

a) 25
b) 75
c) 50 
d) 100

To get uniform flow, free from turbulence, venturimeter should be preceded by straight pipe (from valve, bend, etc.) for a length of not less than 50 times its diameter.

Q.9. According to Lacey’s silt theory, perimeter P of a channel is proportional to (where Q is discharge)

a) Q²/⁵ 
b) Q¹/² 
c) Q⁴/⁵
d) Q

Q.10. The test suitable for conducting in the laboratory as well as on site for finding shear strength of cohesive soil is

a) direct shear test
b) triaxial test
c) vane shear test 
d) all the above

Q.11. Lokpriya Gopinath Bordoloi International Airport is located at :

a) Jaipur
b) Banglore
c) Guwahati 
d) Hyderabad

Q.12. A man buys an article for Rs 490 and sells it for Rs 465.50. Find his loss percentage.

a) 4 %
b) 4.5 %
c) 5 % 
d) 5.5 %

Cost Price (C.P.) = 490 rupees,
Selling Price (S.P.) = 465.50
Loss = C.P. - S.P. = 490 - 465.50 = 24.5
loss percentage = Loss/C.P. x100
                          = 24.5/490 x 100
                          = 5 %

Q.13. Find the angle between the hour hand and the minute hand of a clock when the time is 10.25 hours i.e. 25 minutes past 10 ?

a) 180°
b) 165°
c) 162.5° 
d) 152.5°

angle between the two hands = 30 H - (11/2)M
                                               = 30 x 10 - (11/2) 25 =162.5°

Q.14. The Indian Standard Time (I.S.T.) is ahead  of Greenwich Mean Time (G.M.T.) by :

a) 6 hours
b) 5 hours
c) 6 hours 30 minutes
d) 5 hours 30 minutes 

Q.15. Which company will use ISRO’s NavIC navigation technology in its upcoming smartphones for the first time in the world?

a) Samsung
b) Realme 
c) Nokia
d) Vivo


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